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标题: 请教稀土配合物优化失败如何解决 [打印本页]
作者Author: bomsaude 时间: 2014-12-17 18:33
标题: 请教稀土配合物优化失败如何解决
本帖最后由 bomsaude 于 2014-12-17 18:59 编辑
接触高斯有半年了,原先按书上和网上的一些小分子进行了了一些演练,现在想练习一些大一点的分子,几何优化就不收敛了。稀土配合物是最常见的Eu(TTA)3phen,C H O N F采用6-31g基组,S采用6-31g(d)基组,Eu采用赝势基组,输入文件如下,不知道有什么不对或不合适的地方?看到文献上写All the molecular structures were fully optimized in the gas-phase without symmetry restrictions by the gradient procedure,那么关键词中用不用加nosymm?
log文件的部分内容如下
- ......
- There are 685 symmetry adapted basis functions of A symmetry.
- Integral buffers will be 131072 words long.
- Raffenetti 2 integral format.
- Two-electron integral symmetry is turned on.
- 685 basis functions, 1685 primitive gaussians, 723 cartesian basis functions
- 231 alpha electrons 231 beta electrons
- nuclear repulsion energy 11089.1497305945 Hartrees.
- NAtoms= 77 NActive= 77 NUniq= 77 SFac= 1.00D+00 NAtFMM= 50 NAOKFM=T Big=T
- One-electron integrals computed using PRISM.
- 1 Symmetry operations used in ECPInt.
- ECPInt: NShTT= 29890 NPrTT= 254997 LenC2= 21948 LenP2D= 80677.
- LDataN: DoStor=T MaxTD1= 9 Len= 602
- NBasis= 685 RedAO= T NBF= 685
- NBsUse= 685 1.00D-06 NBFU= 685
- Defaulting to unpruned grid for atomic number 63.
- Harris functional with IExCor= 402 diagonalized for initial guess.
- ExpMin= 2.27D-02 ExpMax= 7.01D+04 ExpMxC= 1.08D+04 IAcc=3 IRadAn= 0 AccDes= 0.00D+00
- HarFok: IExCor= 402 AccDes= 0.00D+00 IRadAn= 0 IDoV= 1
- ScaDFX= 1.000000 1.000000 1.000000 1.000000
- Defaulting to unpruned grid for atomic number 63.
- Defaulting to unpruned grid for atomic number 63.
- FoFCou: FMM=F IPFlag= 0 FMFlag= 100000 FMFlg1= 2001
- NFxFlg= 0 DoJE=T BraDBF=F KetDBF=T FulRan=T
- Omega= 0.000000 0.000000 1.000000 0.000000 0.000000 ICntrl= 500 IOpCl= 0
- NMat0= 1 NMatS0= 1 NMatT0= 0 NMatD0= 1 NMtDS0= 0 NMtDT0= 0
- I1Cent= 4 NGrid= 0.
- ......
- The electronic state of the initial guess is 1-A.
- Requested convergence on RMS density matrix=1.00D-08 within 128 cycles.
- Requested convergence on MAX density matrix=1.00D-06.
- Requested convergence on energy=1.00D-06.
- No special actions if energy rises.
- Defaulting to unpruned grid for atomic number 63.
- Defaulting to unpruned grid for atomic number 63.
- EnCoef did 3 forward-backward iterations
- EnCoef did 100 forward-backward iterations
- EnCoef did 100 forward-backward iterations
- EnCoef did 100 forward-backward iterations
- EnCoef did 4 forward-backward iterations
- Restarting incremental Fock formation.
- Matrix for removal 4 Erem= -4537.45091694709 Crem= 0.000D+00
- Matrix for removal 3 Erem= -4639.05934792761 Crem= 0.000D+00
- Matrix for removal 3 Erem= -4702.55800949193 Crem= 0.000D+00
- Matrix for removal 3 Erem= -4723.24313399146 Crem= 0.000D+00
- Restarting incremental Fock formation.
- Restarting incremental Fock formation.
- Restarting incremental Fock formation.
- Restarting incremental Fock formation.
- Restarting incremental Fock formation.
- >>>>>>>>>> Convergence criterion not met.
- SCF Done: E(RB3LYP) = -4746.74628519 A.U. after 129 cycles
- Convg = 0.7593D-05 -V/T = 2.0847
- Convergence failure -- run terminated.
- Error termination via Lnk1e in /home/user/g09/l502.exe at Wed Dec 17 00:33:33 2014.
- Job cpu time: 0 days 15 hours 52 minutes 36.1 seconds.
- File lengths (MBytes): RWF= 250 Int= 0 D2E= 0 Chk= 8 Scr= 1</font>
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出现这种情况,我应该增大循环次数还是修改收敛标准?望有经验的人给予指点,谢谢了!
作者Author: sobereva 时间: 2014-12-17 20:03
如果初始结构本身就没有对称性就不用加nosymm
解决SCF不收敛没有万能的办法,有可能解决此问题的方法在此贴有汇总:
解决SCF不收敛问题的方法
http://sobereva.com/61
应结合实际情况,将其中的方法挨个试试,或者组合使用。增大循环次数是最没用、还白浪费计算时间的做法。
过渡金属体系不容易收敛是正常的。
另外应当用#P,输出迭代的细节信息,以便于监控收敛到了什么程度,这有助于选择合适的方法帮助收敛。
作者Author: bomsaude 时间: 2014-12-18 00:02
谢谢,我按照您说的方法试试看。
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