计算化学公社
标题:
求助单轴拉伸应力和应变的关系异常
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作者Author:
潇潇的kk
时间:
2025-7-2 10:49
标题:
求助单轴拉伸应力和应变的关系异常
各位老师,我在做单轴拉伸应变的时候,应力和应变的关系如图。我看文献中的没有小尾巴出现,要么突然断裂要么塑性形变。我想问是我做的哪个地方不对吗?(附上我的INCAR)
作者Author:
chenfei
时间:
2025-7-4 19:48
弹性常数计算是利用有限差分法计算,你这静态计算前是否将结构优化至收敛,最好附上outcar文件,可以查看收敛情况。
作者Author:
lrl@qhu
时间:
2025-11-12 13:55
楼主您好,最近我也在学习界面模型的单轴拉伸,有几点问题想向您请教:
1.计算应力应变需要重新编译vasp固定轴吗?
2.我采用的vaspkit生成的一系列的C文件夹下面有不同应力应变的文件夹,问ai是计算单个C33的即可对应拉伸c轴。
但是计算结果全为负值,这是什么原因?
== strain_0.000/ ===
in kB -2.29707 -2.29707 -7.40960 0.00000 0.00000 0.00000
external pressure = -4.00 kB Pullay stress = 0.00 kB
=== strain_+0.025/ ===
in kB -7.46276 -7.46276 -23.66026 0.00000 0.00000 0.00000
external pressure = -12.86 kB Pullay stress = 0.00 kB
=== strain_+0.050/ ===
in kB -12.03457 -12.03457 -36.66675 0.00000 0.00000 -0.00000
external pressure = -20.25 kB Pullay stress = 0.00 kB
=== strain_+0.075/ ===
in kB -16.45010 -16.45010 -46.55441 0.00000 0.00000 -0.00000
external pressure = -26.48 kB Pullay stress = 0.00 kB
=== strain_+0.100/ ===
in kB -21.12315 -21.12315 -52.19550 0.00000 -0.00000 0.00000
external pressure = -31.48 kB Pullay stress = 0.00 kB
=== strain_+0.125/ ===
in kB -25.45490 -25.45490 -55.57070 0.00000 0.00000 0.00000
external pressure = -35.49 kB Pullay stress = 0.00 kB
=== strain_+0.150/ ===
in kB -29.14567 -29.14567 -58.00326 0.00000 0.00000 0.00000
external pressure = -38.76 kB Pullay stress = 0.00 kB
=== strain_+0.175/ ===
in kB -32.49653 -32.49653 -59.27669 0.00000 0.00000 -0.00000
external pressure = -41.42 kB Pullay stress = 0.00 kB
=== strain_+0.200/ ===
in kB -35.04080 -35.04080 -60.77160 0.00000 0.00000 -0.00000
external pressure = -43.62 kB Pullay stress = 0.00 kB
=== strain_+0.250/ ===
in kB -38.17822 -38.17822 -63.92614 0.00000 0.00000 0.00000
external pressure = -46.76 kB Pullay stress = 0.00 kB
=== strain_+0.300/ ===
in kB -40.00768 -40.00768 -65.45294 0.00000 0.00000 0.00000
external pressure = -48.49 kB Pullay stress = 0.00 kB
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