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用VASP计算N2H4的能量,在添加IDIPOL=4后,虽然收敛,但能量异常,这样得到的能量是否可用?还是有什么问题?
INCAR
SYSTEM = N2H4
ALGO = Normal
EDIFF = 0.0001
EDIFFG = -0.02
ENCUT = 400
GGA = PE
IBRION = 2
ICHARG = 2
ISIF = 2
#ISTART = 0
ISMEAR = 0
ISPIN = 2
IVDW = 12
LCHARG = .FALSE.
LDAU = .FALSE.
LORBIT = 11
LREAL = Auto
LWAVE = .TRUE.
NELM = 60
NELMIN = 8
NSW = 50
PREC = Accurate
SIGMA = 0.05
IDIPOL = 4
OSZICAR
1 F= -.30247596E+02 E0= -.30247596E+02 d E =-.302476E+02 mag= -0.0003
2 F= -.30323435E+02 E0= -.30323435E+02 d E =-.758395E-01 mag= -0.0000
3 F= -.30315348E+02 E0= -.30315348E+02 d E =-.677518E-01 mag= 0.0000
4 F= -.30323074E+02 E0= -.30323074E+02 d E =-.754787E-01 mag= 0.0000
5 F= -.30007860E+02 E0= -.30007860E+02 d E =0.315215E+00 mag= 0.0000
6 F= -.30323594E+02 E0= -.30323594E+02 d E =-.519599E-03 mag= 0.0000
7 F= -.30323856E+02 E0= -.30323856E+02 d E =-.261617E-03 mag= 0.0000
8 F= -.25362899E+02 E0= -.25362899E+02 d E =0.496070E+01 mag= 0.0000
9 F= -.30272368E+02 E0= -.30272368E+02 d E =0.512264E-01 mag= 0.0000
10 F= -.30080011E+02 E0= -.30080011E+02 d E =0.243583E+00 mag= -0.0000
11 F= -.30324424E+02 E0= -.30324424E+02 d E =-.244413E+00 mag= -0.0000
12 F= -.30159867E+02 E0= -.30159867E+02 d E =-.798558E-01 mag= -0.0000
13 F= -.30324698E+02 E0= -.30324698E+02 d E =-.164831E+00 mag= -0.0000
14 F= -.28072250E+02 E0= -.28072250E+02 d E =0.208762E+01 mag= 0.0000
15 F= -.30218702E+02 E0= -.30218702E+02 d E =-.214645E+01 mag= -0.0000
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