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本帖最后由 Tznameswu 于 2020-9-3 17:07 编辑
老师您好,想请教您一个分子,S1的吸收和发射振子强度均为0。
——可能因为对称性分子,S2和S3的TD吸收一样:
# 3.3035 eV 375.31 nm f= 0.05810 Spin multiplicity= 1: H -> L 76.6%, H-1 -> L+1 21.1% 。
——优化S2后做发射得到:
Excited State 1: Singlet-?Sym 3.2506 eV 381.42 nm f=0.0007 <S**2>=0.000
149 ->151 -0.10499
149 ->152 0.68496
Excited state symmetry could not be determined.
Excited State 2: Singlet-?Sym 3.2608 eV 380.23 nm f=0.0822 <S**2>=0.000
148 ->151 -0.28791
149 ->150 0.63697
This state for optimization and/or second-order correction.
Total Energy, E(TD-HF/TD-KS) = -1840.64346008
Copying the excited state density for this state as the 1-particle RhoCI density.
Excited state symmetry could not be determined.
Excited State 3: Singlet-?Sym 3.2911 eV 376.72 nm f=0.0494 <S**2>=0.000
148 ->150 0.33473
149 ->151 0.60397
149 ->152 0.10687
这样的分子应该如何解释呢?先谢谢老师了
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