|
|
我最近发现一个体系在乙腈中有S2发光的迹象,所以考虑优化了它的S2态opt pbe1pbe 6-31g** td=(singlets,nstates=5,root=2) scrf=(solvent=acetonitrile) nosymm
但是发现优化到中途,出现了S3比S2低的情况:
Excited state symmetry could not be determined.
Excited State 1: Singlet-?Sym 1.6909 eV 733.26 nm f=1.1235 <S**2>=0.000
115 ->116 0.70147
Excited state symmetry could not be determined.
Excited State 2: Singlet-?Sym 2.9238 eV 424.05 nm f=0.4253 <S**2>=0.000
113 ->116 -0.70158
This state for optimization and/or second-order correction.
Total Energy, E(TD-HF/TD-KS) = -1393.55714679
Copying the excited state density for this state as the 1-particle RhoCI density.
Excited state symmetry could not be determined.
Excited State 3: Singlet-?Sym 2.1672 eV 572.10 nm f=0.3037 <S**2>=0.000
114 ->116 0.70330
Excited state symmetry could not be determined.
Excited State 4: Singlet-?Sym 3.4762 eV 356.67 nm f=0.0033 <S**2>=0.000
111 ->116 -0.11784
112 ->116 0.69295
Excited state symmetry could not be determined.
Excited State 5: Singlet-?Sym 3.4881 eV 355.45 nm f=0.0113 <S**2>=0.000
108 ->116 -0.20594
111 ->116 0.65553
112 ->116 0.12530
然后之后一直算下去都是S3比S2低了
所以我考虑可能是S3和S2有交叉,但是我想找的是第二激发态的能量最低点,这样优化下去还有意义吗?
我现在考虑可能那个更低的S3是我想要的态,想取这个优化的中途的结构来继续算,那么是应该去优化S3还是S2呢?
|
|