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各位老师和同学好:
我有一个蛋白(nlrp3),我们自己设计了一个化合物(st4),我们想研究st4与nlrp3相互作用关系,我们使用moe将st4的C和nlrp3的S连接后,导出为pdb结构,然后按照Amber教程 使用Antechamber处理小分子st4(将CYS改成CYP,将ST4也改成CYP,作为一个整体处理,因为分开处理时缺少c-sh-c信息),得到了nlrp3.prmtop和nlrp3.inpcrd文件,使用命令ambpdb -p nlrp3.prmtop < nlrp3.inpcrd > nlrp3_ambpdb_leap.pdb,生成了nlrp3_ambpdb_leap.pdb(见附件),将其导入pymol后检查并没有问题,只是CYP“残基”上下多了两个TER,如下:
ATOM 2481 O SER 149 -5.850 -12.074 -12.570 1.00 0.00
TER
ATOM 2482 N CYP 150 -7.662 -12.808 -11.462 1.00 0.00
ATOM 2483 CA CYP 150 -7.000 -13.292 -10.238 1.00 0.00
ATOM 2484 CB CYP 150 -7.754 -12.931 -8.954 1.00 0.00
ATOM 2485 SG CYP 150 -7.620 -11.129 -8.594 1.00 0.00
ATOM 2486 C CYP 150 -6.544 -14.760 -10.228 1.00 0.00
ATOM 2487 O CYP 150 -6.039 -15.224 -9.207 1.00 0.00
ATOM 2488 H7 CYP 150 -8.575 -13.209 -11.528 1.00 0.00
ATOM 2489 H8 CYP 150 -7.122 -13.075 -12.261 1.00 0.00
ATOM 2490 H9 CYP 150 -6.087 -12.891 -10.172 1.00 0.00
ATOM 2491 H10 CYP 150 -7.552 -13.608 -8.247 1.00 0.00
ATOM 2492 H11 CYP 150 -8.737 -12.923 -9.136 1.00 0.00
ATOM 2493 H12 CYP 150 -5.756 -14.869 -10.836 1.00 0.00
ATOM 2494 C1 CYP 150 -6.079 -10.508 -9.452 1.00 0.00
ATOM 2495 C2 CYP 150 -3.691 -10.220 -11.048 1.00 0.00
ATOM 2496 C3 CYP 150 -3.752 -11.531 -10.212 1.00 0.00
ATOM 2497 O1 CYP 150 -4.081 -12.680 -10.923 1.00 0.00
ATOM 2498 C4 CYP 150 -4.666 -11.127 -9.022 1.00 0.00
ATOM 2499 C5 CYP 150 -3.771 -9.965 -8.677 1.00 0.00
ATOM 2500 C6 CYP 150 -3.017 -9.399 -9.934 1.00 0.00
ATOM 2501 C7 CYP 150 -3.230 -7.859 -9.876 1.00 0.00
ATOM 2502 C8 CYP 150 -2.086 -7.302 -8.996 1.00 0.00
ATOM 2503 C9 CYP 150 -0.664 -7.473 -9.587 1.00 0.00
ATOM 2504 C10 CYP 150 -0.543 -8.696 -10.544 1.00 0.00
ATOM 2505 C11 CYP 150 0.922 -9.178 -10.730 1.00 0.00
ATOM 2506 C12 CYP 150 1.927 -8.017 -10.651 1.00 0.00
ATOM 2507 C13 CYP 150 -0.925 -8.283 -12.006 1.00 0.00
ATOM 2508 C14 CYP 150 0.504 -7.325 -8.555 1.00 0.00
ATOM 2509 C15 CYP 150 1.830 -7.203 -9.359 1.00 0.00
ATOM 2510 C16 CYP 150 0.526 -8.522 -7.561 1.00 0.00
ATOM 2511 O2 CYP 150 -3.497 -9.720 -7.537 1.00 0.00
ATOM 2512 C17 CYP 150 -2.355 -12.055 -9.691 1.00 0.00
ATOM 2513 C18 CYP 150 -1.277 -11.041 -9.223 1.00 0.00
ATOM 2514 C19 CYP 150 -1.503 -9.856 -10.163 1.00 0.00
ATOM 2515 C20 CYP 150 0.466 -6.038 -7.707 1.00 0.00
ATOM 2516 O3 CYP 150 0.648 -6.025 -6.491 1.00 0.00
ATOM 2517 O4 CYP 150 0.365 -4.882 -8.384 1.00 0.00
ATOM 2518 H25 CYP 150 -5.985 -9.525 -9.299 1.00 0.00
ATOM 2519 H26 CYP 150 -6.149 -10.688 -10.433 1.00 0.00
ATOM 2520 H27 CYP 150 -4.618 -9.944 -11.303 1.00 0.00
ATOM 2521 H28 CYP 150 -3.150 -10.374 -11.875 1.00 0.00
ATOM 2522 H29 CYP 150 -3.416 -12.821 -11.656 1.00 0.00
ATOM 2523 H30 CYP 150 -4.783 -11.696 -8.208 1.00 0.00
ATOM 2524 H32 CYP 150 -4.124 -7.661 -9.473 1.00 0.00
ATOM 2525 H33 CYP 150 -3.190 -7.481 -10.801 1.00 0.00
ATOM 2526 H34 CYP 150 -2.076 -7.781 -8.119 1.00 0.00
ATOM 2527 H35 CYP 150 -2.231 -6.324 -8.840 1.00 0.00
ATOM 2528 H36 CYP 150 -0.425 -6.662 -10.121 1.00 0.00
ATOM 2529 H37 CYP 150 1.019 -9.612 -11.626 1.00 0.00
ATOM 2530 H38 CYP 150 1.150 -9.837 -10.014 1.00 0.00
ATOM 2531 H39 CYP 150 1.777 -7.393 -11.418 1.00 0.00
ATOM 2532 H40 CYP 150 2.858 -8.379 -10.692 1.00 0.00
ATOM 2533 H41 CYP 150 -1.867 -7.948 -12.023 1.00 0.00
ATOM 2534 H42 CYP 150 -0.843 -9.077 -12.609 1.00 0.00
ATOM 2535 H43 CYP 150 -0.309 -7.560 -12.321 1.00 0.00
ATOM 2536 H44 CYP 150 1.960 -6.233 -9.566 1.00 0.00
ATOM 2537 H45 CYP 150 2.538 -7.504 -8.721 1.00 0.00
ATOM 2538 H46 CYP 150 0.662 -9.374 -8.068 1.00 0.00
ATOM 2539 H47 CYP 150 -0.342 -8.562 -7.068 1.00 0.00
ATOM 2540 H48 CYP 150 1.274 -8.400 -6.909 1.00 0.00
ATOM 2541 H50 CYP 150 -1.903 -12.576 -10.415 1.00 0.00
ATOM 2542 H51 CYP 150 -2.496 -12.645 -8.895 1.00 0.00
ATOM 2543 H52 CYP 150 -0.372 -11.463 -9.283 1.00 0.00
ATOM 2544 H53 CYP 150 -1.458 -10.774 -8.276 1.00 0.00
ATOM 2545 H54 CYP 150 -1.722 -10.194 -11.079 1.00 0.00
ATOM 2546 H56 CYP 150 0.199 -5.224 -6.095 1.00 0.00
TER
ATOM 2547 N CYS 151 -6.695 -15.498 -11.328 1.00 0.00
紧着这,使用生成的nlrp3.prmtop和nlrp3.inpcrd文件进行能量最小化,输入如下(min.in):
Initial minimisation of NLRP3-ST4 complex
&cntrl
imin=1, maxcyc=200, ncyc=50,
cut=16, ntb=0, igb=1,
ntr=1, restraint_wt=10.0, restraintmask='!:WAT & !@H=',
&end
运行命令
mpirun -n 8 sander.MPI -O -p nlrp3.prmtop -c nlrp3.inpcrd -ref nlrp3.inpcrd -i min.in -o min.out -r min.rst &
cpptraj -p nlrp3.prmtop -y min.rst -x min.rst7
查看min.rst7文件,内容如下:
Cpptraj Generated Restart
76006 0.0000000E+00
-nan -nan -nan -nan -nan -nan
-nan -nan -nan -nan -nan -nan
-nan -nan -nan -nan -nan -nan
.....
生成pdb内容:
ATOM 1 N GLY 1 nan nan nan 1.00 0.00 N
ATOM 2 H1 GLY 1 nan nan nan 1.00 0.00 H
ATOM 3 H2 GLY 1 nan nan nan 1.00 0.00 H
ATOM 4 H3 GLY 1 nan nan nan 1.00 0.00 H
ATOM 5 CA GLY 1 nan nan nan 1.00 0.00 C
ATOM 6 HA2 GLY 1 nan nan nan 1.00 0.00 H
ATOM 7 HA3 GLY 1 nan nan nan 1.00 0.00 H
......
查看min.ou文件:
--------------------------------------------------------------------------------
4. RESULTS
--------------------------------------------------------------------------------
NSTEP ENERGY RMS GMAX NAME NUMBER
1 NaN NaN 1.0878E+02 HG3 953
BOND = 607.6586 ANGLE = 1779.2615 DIHED = 6822.3541
VDWAALS = NaN EEL = Infinity EGB = NaN
1-4 VDW = 2240.6465 1-4 EEL = 20819.8067 RESTRAINT = 0.0000
NSTEP ENERGY RMS GMAX NAME NUMBER
50 NaN NaN 0.0000E+00 N 1
BOND = NaN ANGLE = NaN DIHED = NaN
VDWAALS = 0.0000 EEL = 0.0000 EGB = -3709683.6084
1-4 VDW = NaN 1-4 EEL = NaN RESTRAINT = NaN
EAMBER = NaN
.....
请问大家,这是哪里出错啊?
另外,最小化中将ntb=0, igb=1,改为ntb=1,将出现报错
$ sander -O -i min.in -o nlrp3_min_.out -p nlrp3.prmtop -c nlrp3.inpcrd -ref nlrp3.inpcrd -r nlrp3_min_.crd
forrtl: severe (174): SIGSEGV, segmentation fault occurred
Image PC Routine Line Source
sander 0000000000DB8E14 for__signal_handl Unknown Unknown
libpthread-2.17.s 00002B2E75D175F0 Unknown Unknown Unknown
sander 00000000007C2A80 short_ene_ Unknown Unknown
sander 00000000007B7EDB get_nb_energy_ Unknown Unknown
sander 00000000007781ED ewald_force_ Unknown Unknown
sander 00000000006892DC force_ Unknown Unknown
sander 0000000000703286 runmin_ Unknown Unknown
sander 00000000006EC37F sander_ Unknown Unknown
sander 00000000006E3116 MAIN__ Unknown Unknown
sander 0000000000465B5E main Unknown Unknown
libc-2.17.so 00002B2E77822505 __libc_start_main Unknown Unknown
sander 0000000000465A69 Unknown Unknown Unknown
这又是为什么呢?
min.out
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