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本帖最后由 Maxwell03 于 2021-5-8 08:53 编辑
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背景:计算该反应的过渡态时,才开始利用柔性扫描,从产物出发,扩大co键之间的距离,所得输出文件如下图图片
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之后限制性优化无果
我打算反向扫描,从反应物出发,缩短co键之间的键长输入文件如下,但老师说我的输入文件是错的,让我自行解决,还把 23 45 s 10 -0.1这一行以及上图的扩大co键之间的截图单独圈出,反应物键长2.4产物1.6大致差了1。
求助:请问我的出错点在哪?思路问题?还是其他?(实在检查不出了!)
%mem=15gb
%nproc=8
#p m062x/def2svp opt=modredundant scrf=(smd,solvent=2-Methyl-2-Propanol) int=ultrafine
adf
-1 1
C -1.11775700 0.37984200 1.89985500
C -0.24178600 0.79134700 2.91525700
C 0.47891300 1.96833300 2.78306200
C 0.33872800 2.74901200 1.62679900
C -0.52372000 2.34768100 0.61040800
C -1.26715000 1.14603800 0.74738700
H -1.67071100 -0.55380900 2.00882200
H -0.13444300 0.17372300 3.80858500
H 1.16150900 2.29358100 3.56985300
H 0.91645000 3.66710300 1.52309000
O -0.70179400 3.01453700 -0.55212500
C 0.05660200 4.18173600 -0.76599500
H -0.22065300 4.55777300 -1.75765500
H -0.16849300 4.95451900 -0.01295900
H 1.13816400 3.96695200 -0.75036300
O -2.06298800 0.84503200 -0.30326300
C -2.58230300 -0.47232800 -0.54171400
C -3.64757400 -0.85880200 0.52728200
H -4.54034700 -1.16766200 -0.03950300
H -3.90644500 0.04717900 1.09428600
O -3.27434700 -1.84592900 1.45415900
H -2.99557200 -2.62112300 0.94237200
C -1.42649700 -1.51525600 -0.69285600
O -1.73344700 -2.69031000 -0.59529000
C 0.00827600 -1.10689100 -0.78890700
C 0.92968100 -1.87323600 -0.05091200
C 0.44750400 -0.00850700 -1.51988800
C 2.27076000 -1.51783900 -0.01147700
H 0.56632100 -2.73623400 0.50659100
C 1.79796700 0.35108200 -1.49318200
H -0.28294300 0.54743000 -2.10478600
C 2.71210400 -0.38059700 -0.73709100
H 2.13305600 1.21278200 -2.07002400
O 3.22463500 -2.17520500 0.68714500
O 4.02518700 -0.09499700 -0.63247500
C 2.82307200 -3.28785000 1.45387700
H 2.08256800 -3.00081600 2.21815000
H 2.39828600 -4.08257300 0.81955400
H 3.72333800 -3.66789100 1.95043700
C 4.50688000 1.06040700 -1.28261700
H 3.99673100 1.96659400 -0.91746400
H 5.57534800 1.12775000 -1.04786600
H 4.38190000 0.98989900 -2.37493800
O -3.22154000 -0.44112900 -1.73762000
O -2.19773700 -0.53702600 -2.75076900
23 45 s 10 -0.1
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