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本帖最后由 jio 于 2026-6-1 13:32 编辑
我在计算FeCoSNC双原子催化剂的差分电荷密度,引入了一个-OH预吸附,主要想看看Fe、Co与S之间的电荷转移。差分电荷密度公式:Δρ = ρ_system - ρ _atom1 - ρ_atom2 - ... - ρ_atomN,我应该如何分解组分比较好呢?初步打算是Δρ = ρ_system - ρ _without(FeCo) - ρ_without(S),这样对不对呢?
以及,XPS测试结果表明,S向Fe提供电子,但是我的差分电荷密度和Bader电荷分析却表明Fe失电子,S得电子,这是不是算错了呢?应该如何修正呢?以下是我的INCAR文件:
SYSTEM = qvasp
INCAR-basic
PREC = Normal
ENCUT = 520 eV
NELMIN= 5
LREAL = Auto
ALGO = Fast
EDIFF = 1E-4
ISMEAR = 0
ISPIN = 2
MAGMOM = 50*0 6*0 1*-1.0 1*5.0 1*0 1*0 1*0
LORBIT = 11
SIGMA = 0.1
NPAR = 4 ## important to reduce calculate time, equal sqrt(cpu cores)
Ionic Relaxation
ICHARG = 2
EDIFFG = -0.03 force
NSW = 0 max steps for IOM
IBRION = -1
POTIM = 0.1
ISIF = 2 suface:2 crystal:3
PSTRESS= 0
LCHARG = .TRUE.
LWAVE = .FALSE.
LAECHG = .TRUE.
DFT-D3
IVDW = 12
DFT+U
LDAU = .TRUE.
LDAUTYPE = 2
LDAUL = -1 -1 2 2 -1 -1 -1
LDAUU = 0.0 0.0 4.0 3.0 0.0 0.0 0.0
LDAUJ = 0.0 0.0 0.0 0.0 0.0 0.0 0.0
LMAXMIX = 4
LASPH = .TRUE.
LDAUPRINT = 2
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