计算化学公社

 找回密码 Forget password
 注册 Register
Views: 368|回复 Reply: 1
打印 Print 上一主题 Last thread 下一主题 Next thread

[综合交流] 关于考虑周期性镜像的静电势能计算公式问题

[复制链接 Copy URL]

17

帖子

0

威望

199

eV
积分
216

Level 3 能力者

在计算静电势能时,在比较多地方看到的都是如图这个公式。但我有一点疑惑的地方是,比如假设盒子有3个粒子,并考虑一个周期镜像与盒子的相互作用,求和号中n=0时有6对相互作用(排除i=j的情况),n=1时有9对相互作用,加起来15对,除以2后是7.5对?感觉是不是n=0时才需要除以2,n≠0时不需要除以2?

1.png (121.47 KB, 下载次数 Times of downloads: 0)

1.png

59

帖子

0

威望

913

eV
积分
972

Level 4 (黑子)

2#
发表于 Post on 2025-7-18 21:38:05 | 只看该作者 Only view this author
Sorry, my work computer can not type Chinese.

The answer should be no. Because you take one box from the periodic system to calculate the system potential energy, not the box potential energy. If the equation is as you saying, it double considers the energy contribution between two different boxes. For example, you take box 1 and consider the contribution from box 2, the total potential is U, this U is shared by box 1 and 2, or you will have U on box 1 and U on box 2, the total energy of this two boxes, if you take this two together as one box, the energy is 2U, not U.

本版积分规则 Credits rule

手机版 Mobile version|北京科音自然科学研究中心 Beijing Kein Research Center for Natural Sciences|京公网安备 11010502035419号|计算化学公社 — 北京科音旗下高水平计算化学交流论坛 ( 京ICP备14038949号-1 )|网站地图

GMT+8, 2025-8-12 22:02 , Processed in 0.168627 second(s), 23 queries , Gzip On.

快速回复 返回顶部 返回列表 Return to list