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大家好,我的振动分析作业最后结束是这样的,第一次遇见这样的,不知道是报错还是正常结束的作业.一般不都是 Normal termination of Gaussian 09这样的提示吗?这种属于什么情况呢?麻烦大家给看看,谢谢了
Error on total polarization charges = 0.07217
SCF Done: E(UB3LYP) = -3979.10686246 A.U. after 40 cycles
NFock= 40 Conv=0.15D-08 -V/T= 2.0197
<Sx>= 0.0000 <Sy>= 0.0000 <Sz>= 0.0000 <S**2>= 1.0096 S= 0.6223
<L.S>= 0.000000000000E+00
KE= 3.902054593889D+03 PE=-3.798347229595D+04 EE= 1.578483701450D+04
SMD-CDS (non-electrostatic) energy (kcal/mol) = 15.37
(included in total energy above)
Annihilation of the first spin contaminant:
S**2 before annihilation 1.0096, after 0.0810
Leave Link 502 at Sat Aug 24 16:02:00 2019, MaxMem= 2013265920 cpu: 27920.6
(Enter /share/apps/g09d01/g09/l801.exe)
DoSCS=F DFT=T ScalE2(SS,OS)= 1.000000 1.000000
Range of M.O.s used for correlation: 1 1192
NBasis= 1192 NAE= 286 NBE= 286 NFC= 0 NFV= 0
NROrb= 1192 NOA= 286 NOB= 286 NVA= 906 NVB= 906
**** Warning!!: The smallest alpha delta epsilon is 0.88694351D-01
**** Warning!!: The smallest beta delta epsilon is 0.89450291D-01
Leave Link 801 at Sat Aug 24 16:02:01 2019, MaxMem= 2013265920 cpu: 0.5
(Enter /share/apps/g09d01/g09/l1101.exe)
Using compressed storage, NAtomX= 146.
Will process 147 centers per pass.
PrsmSu: requested number of processors reduced to: 5 ShMem 1 Linda.
1 Symmetry operations used in ECPInt.
ECPInt: NShTT= 99235 NPrTT= 622615 LenC2= 59157 LenP2D= 172652.
LDataN: DoStor=T MaxTD1= 5 Len= 102
Number of processors reduced to 2 by ecpmxn.
R6Disp: Adding Grimme-D3 dispersion energy 1st derivatives to the gradient.
Leave Link 1101 at Sat Aug 24 16:02:30 2019, MaxMem= 2013265920 cpu: 169.6
(Enter /share/apps/g09d01/g09/l1102.exe)
Symmetrizing basis deriv contribution to polar:
IMax=3 JMax=2 DiffMx= 0.00D+00
Leave Link 1102 at Sat Aug 24 16:02:54 2019, MaxMem= 2013265920 cpu: 155.8
(Enter /share/apps/g09d01/g09/l1110.exe)
Forming Gx(P) for the SCF density, NAtomX= 146.
Integral derivatives from FoFJK, PRISM(SPDF).
Do as many integral derivatives as possible in FoFJK.
G2DrvN: MDV= 2013264648.
G2DrvN: will do 37 centers at a time, making 4 passes.
G2DrvN: IPasSy=1 do centers 0 through 36.
Calling FoFCou, ICntrl= 3107 FMM=T I1Cent= 0 AccDes= 0.00D+00.
FoFJK: IHMeth= 1 ICntrl= 3107 DoSepK=F KAlg= 0 I1Cent= 0 FoldK=F
IRaf= 0 NMat= 1 IRICut= 1 DoRegI=T DoRafI=F ISym2E= 0.
FoFCou: FMM=T IPFlag= 0 FMFlag= 100000 FMFlg1= 2001
NFxFlg= 0 DoJE=F BraDBF=F KetDBF=F FulRan=T
wScrn= 0.000000 ICntrl= 3107 IOpCl= 1 I1Cent= 0 NGrid= 0
NMat0= 1 NMatS0= 1 NMatT0= 0 NMatD0= 1 NMtDS0= 0 NMtDT0= 0
Symmetry not used in FoFCou.
FMM levels: 10 Number of levels for PrismC: 9
G2DrvN: IPasSy=1 do centers 37 through 73.
Calling FoFCou, ICntrl= 3107 FMM=T I1Cent= 0 AccDes= 0.00D+00.
G2DrvN: IPasSy=1 do centers 74 through 110.
Calling FoFCou, ICntrl= 3107 FMM=T I1Cent= 0 AccDes= 0.00D+00.
G2DrvN: IPasSy=1 do centers 111 through 146.
Calling FoFCou, ICntrl= 3107 FMM=T I1Cent= 0 AccDes= 0.00D+00.
NEqPCM: Using equilibrium solvation (IEInf=0, Eps= 6.0000, EpsInf= 1.7778)
G2PCM: DoFxE=T DoFxN=T DoGrad=T DoDP/DQ/DG/TGxP=FFFF NFrqRd= 0 IEInf=0 SqF1=F DoCFld=F IF1Alg=4.
GePol: Maximum number of non-zero 1st derivatives = 393
End of G2Drv F.D. properties file 721 does not exist.
End of G2Drv F.D. properties file 722 does not exist.
End of G2Drv F.D. properties file 788 does not exist.
Leave Link 1110 at Sat Aug 24 17:46:04 2019, MaxMem= 2013265920 cpu: 49515.3
(Enter /share/apps/g09d01/g09/l1002.exe)
Minotr: UHF open shell wavefunction.
IDoAtm=11111111111111111111111111111111111111111111111111
IDoAtm=11111111111111111111111111111111111111111111111111
IDoAtm=1111111111111111111111111111111111111111111111
NEqPCM: Using equilibrium solvation (IEInf=0, Eps= 6.0000, EpsInf= 1.7778)
Direct CPHF calculation.
Differentiating once with respect to electric field.
with respect to dipole field.
Differentiating once with respect to nuclear coordinates.
Requested convergence is 1.0D-08 RMS, and 1.0D-07 maximum.
Secondary convergence is 1.0D-12 RMS, and 1.0D-12 maximum.
NewPWx=T KeepS1=F KeepF1=F KeepIn=T MapXYZ=F SortEE=F KeepMc=T.
MDV= 2013262072 using IRadAn= 2.
Generate precomputed XC quadrature information.
Solving linear equations simultaneously, MaxMat= 72.
FoF2E skips out because all densities are zero.
CalDSu exits because no D1Ps are significant.
FoFJK: IHMeth= 1 ICntrl= 0 DoSepK=F KAlg= 0 I1Cent= 0 FoldK=F
IRaf= 610000000 NMat= 72 IRICut= 1 DoRegI=T DoRafI=F ISym2E= 0.
There are 441 degrees of freedom in the 1st order CPHF. IDoFFX=6 NUNeed= 3.
441 vectors produced by pass 0 Test12= 5.18D-13 1.00D-09 XBig12= 4.68D+03 2.73D+01.
AX will form 72 AO Fock derivatives at one time.
441 vectors produced by pass 1 Test12= 5.18D-13 1.00D-09 XBig12= 1.13D+03 4.69D+00.
441 vectors produced by pass 2 Test12= 5.18D-13 1.00D-09 XBig12= 1.57D+01 3.49D-01.
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