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附件是我计算CO2非简谐频率的输出文件。有个问题请教一下大家。
以下是立方力常数和四次方力常数,3a和3b对应着简并的弯曲振动。
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: CUBIC FORCE CONSTANTS IN NORMAL MODES :
: :
: FI = Reduced values [cm-1] (default input) :
: k = Cubic Force Const.[AttoJ*amu(-3/2)*Ang(-3)] :
: K = Cubic Force Const.[Hartree*amu(-3/2)*Bohr(-3)] :
:......................................................:
I J K FI(I,J,K) k(I,J,K) K(I,J,K)
1 1 1 264.87753 1.36572 0.04642
2 2 1 506.82404 4.58759 0.15593
3a 3a 1 -158.41000 -0.40183 -0.01366
3b 3b 1 -158.41000 -0.40183 -0.01366
Num. of 3rd derivatives larger than 0.371D-04: 4 over 20
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: :
: QUARTIC FORCE CONSTANTS IN NORMAL MODES :
: :
: FI = Reduced values [cm-1] (default input) :
: k = Quartic Force Const.[AttoJ*amu(-2)*Ang(-4)] :
: K = Quartic Force Const.[Hartree*amu(-2)*Bohr(-4)] :
:......................................................:
I J K L FI(I,J,K,L) k(I,J,K,L) K(I,J,K,L)
1 1 1 1 40.90120 1.34523 0.02420
2 2 1 1 80.40071 4.64230 0.08350
2 2 2 2 161.10262 16.33005 0.29372
3a 3a 1 1 -47.63350 -0.77076 -0.01386
3b 3b 1 1 -47.63350 -0.77076 -0.01386
3a 3a 2 2 -113.42440 -3.22200 -0.05795
3b 3b 2 2 -113.42440 -3.22200 -0.05795
3a 3a 3a 3a 74.08378 0.58976 0.01061
3a 3a 3b 3b 24.69459 0.19659 0.00354
3b 3b 3b 3b 74.08378 0.58976 0.01061
在最后输出fundamental bands时
Fundamental Bands
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Mode(n,l) Status E(harm) E(anharm) Ba(x) Ca(y)
H 1(1,+0) active 1371.890 1406.119 0.389995 0.389995
2(1,+0) active 2408.411 2362.154 0.388094 0.388094
3(1,-1) active 674.939 671.428 0.391912 0.391912
3(1,+1) active 674.939 671.428 0.391912 0.391912
弯曲振动的简谐频率和非简谐频率差很小。
请问非简谐频率与简谐频率,非简谐常数之间的关系式是什么?
谢谢大家。
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