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我尝试通过gic方法,使一个乙烷分子在中心位置相对另一乙烷分子位置(位置固定)确定的情况下,进行优化。
# opt b3lyp/6-31g(d,p) geom=gic
Title Card Required
0 1
C 0 -3.11616551 -0.10136404 -0.07747210
H 0 -3.52940963 0.35783346 0.79617940
H 0 -3.52940963 0.35783346 -0.95112360
H 0 -3.35232462 -1.14497742 -0.07747210
C 0 -1.58674718 0.07885679 -0.07747210
H 0 -1.17350277 -0.38034307 -0.95112223
H 0 -1.35058858 1.12247028 -0.07747446
H 0 -1.17350280 -0.38033854 0.79618043
C -1 1.08660750 1.69629127 0.10644723
H -1 1.44328034 2.20068946 0.98009873
H -1 1.44328034 2.20068946 -0.76720427
H -1 0.01660750 1.69630446 0.10644723
C -1 1.59992321 0.24435912 0.10644723
H -1 1.24325240 -0.26003835 0.98009998
H -1 1.24324834 -0.26003979 -0.76720303
H -1 2.66992321 0.24434593 0.10644474
XC1(freeze)=XCntr(9,13)
YC1(freeze)=YCntr(9,13)
ZC1(freeze)=ZCntr(9,13)
但是计算结束后,两分子之间的距离还是变大了。
(下面是计算结束后的坐标)
# opt b3lyp/6-31g(d,p) geom=gic
Title Card Required
0 1
C 0 3.44379500 -0.17922100 0.39803600
H 0 3.54284800 0.57223400 1.18837100
H 0 3.32958800 -1.15430000 0.88313700
H 0 4.38625300 -0.19711700 -0.15930000
C 0 2.25936900 0.12942600 -0.51995000
H 0 2.15988700 -0.62207100 -1.31017300
H 0 1.31691400 0.14738600 0.03793300
H 0 2.37328300 1.10452900 -1.00497000
C -1 -2.52503600 0.71456400 0.16411700
H -1 -2.89407700 1.39766100 -0.57214900
H -1 -2.76404800 1.07974000 1.14106100
H -1 -1.46326500 0.62466100 0.06684700
C -1 -3.17804900 -0.66477400 -0.04228500
H -1 -2.93903900 -1.02994900 -1.01923000
H -1 -2.80900500 -1.34787100 0.69397900
H -1 -4.23981900 -0.57487100 0.05498700
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